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5 votes
The equation for the circle is:

x2+y2+14x+10y−7=0 .



What is the center of the circle?

1 Answer

1 vote
use completion of sq method
x^2+y^2+14x+10y-7=0
(x+7)^2+(y+5)^2=7+49+25
(x+7)^2+(y+5)^2=81
so centre is(-7,-5) radius is9
answered
User Ahmed Akhtar
by
8.4k points

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