Question

the equation of line wx is y=-2x - 5. write an equation of a line perpendicular to line wx in slope intercept form that contains point (-1,-2)

Answer 1

y=2x-5, with "2" as a slope. Any line perpendicular to y has a slope = -1/2
(the product of the slopes of 2 perpendicular line m₁.m₂ =-1)

The equation of the line perpendicular to "wx" is y=mx +b. we know tye value of m = -1/2, so y = (-1/2)x +b. Moreover y passes through (-1,-2), to find b, plug the related values of x and y; -2 =(-1/2).(-1) +b and b= 5/2

Hence the perpendicular equation y (-1/2)x + 5/2