Question

Write 6(x – 5)4 + 4(x – 5)2 + 6 = 0 in the form of a quadratic by using substitution

Answer 1

the answer is (B) on ed2020

Explanation:

B- 6u2 + 4u + 6 = 0, where u = (x – 5)2

Answer 2

`6u^(2)+4u+6=0`

Explanation:

we have

`6(x-5)^(4)+4(x-5)^(2)+6=0`

Let

`u=(x-5)^(2)`

remember that

if
`u=(x-5)^(2)`

then

`u^(2)=(x-5)^(4)`

substitute

`6u^(2)+4u+6=0` -------> quadratic equation