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What is the percent of N in AgNO3?

What is the percent of N in AgNO3?
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What is the percent of N in AgNO3?

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User Raleigh Buckner
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2 Answers

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AgNO3 Mol mass = 108 + 14 + 48 = 170g/mol.
.N = 14 / 170 = 0.0824 x 100% = 8.24% 'N'.
answered
User Onxx
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4 votes

Answer:

8.24%

Step-by-step explanation:

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User Kabucey
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