Question

Which are the solutions of x2 = –13x – 4? 0, 13 0, –13

Answer 1

Roots are 0 , -13.

Explanation:

Given : x² = –13x – 4.

To find : Which are the solutions.

Solution : We have given that x² +13x + 4 = 0.

By discriminate formula

For quadratic equation a² +bx + c = 0.

`x_(1)` =
`\frac{-b ±\sqrt{b^(2) -4 a * c } }{2}`.

Plugging the values

`x_(1)` =
`\frac{-13 ±\sqrt{13^(2) -4 *1  * 4}}{2}`.

`x_(1)` =
`\frac{-13 +\sqrt{13^(2) -4 *1  * 4}}{2}`.

`x_(1)` =
`(-13 +√(169 - 16))/(2)`.

`x_(1)` =
`(-13 +√(153))/(2)`.

`x_(1)` =
`(-0.6306)/(2)`.

`x_(1)` = -0.3153.

Approximate 0

`x_(2)` =
`\frac{-13 -\sqrt{13^(2) -4 *1  * 4}}{2}`.

`x_(2)` =
`(-13 -√(169 -16))/(2)`.

`x_(2)` =
`(-13 -√(153))/(2)`.

`x_(2)` =
`(-25.36)/(2)`.

`x_(2)` = -12.68

Approximate - 13

Therefore, Roots are 0 , -13.