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Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y2 Is the student’s work correct?
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Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y2 Is the student’s work correct?
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Jun 26, 2018
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Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y2 Is the student’s work correct?
Mathematics
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Choroba
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Answer:
No, she did not use the distributive property correctly
Explanation:
Holz
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Jun 28, 2018
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Holz
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No he's not correct
(3 – 6y2)(y2 + 2)
= 3(y2) -6(y2)(y2) - 6y2(2) + 3(2)
= 3y2 -6y4 - 12y2
+ 6
= -6y4 - 9y2 +6
Martin Booth
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Jul 2, 2018
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Martin Booth
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