Question

A 1.2-liter tank at a temperature of 27°C contains a mixture of 1.5 moles of oxygen, 1.2 moles of nitrogen, and 1.6 moles of hydrogen. What is the total pressure of the mixture inside the tank? (R = 0.0821, L·atm/K·mol)

Answer 1

Ntotal (Nt) = n1 +n2 + n3 = 1.5 + 1.2 + 1.6 = 4.3
PV = nRT --> P = nRT/V
P = (4.3)(.0821)(300)/1.2 = 105.91/1.2
P = 88.26 atm