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Δx→0 −5(x + Δx) + 5x Δx

Δx→0 −5(x + Δx) + 5x Δx
asked 235k views
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Δx→0
−5(x + Δx) + 5x
Δx

asked
User Ckedar
by
8.9k points

1 Answer

1 vote
I guess the original function was

y = 5x (1)

y+Δy =5(x+Δx) (2)

(2) - (1) =

Δy = 5Δx

Δx →0, Δy/Δx →5


answered
User Bhavya
by
7.9k points
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