Question

How many vertical asymptotes does the graph of the function f(x)=2/(x-1)(x+3)(x+8) have

Answer 1

The graph has 3 vertical asymptotes.
x=1 x=-3 x=-8

Answer 2

Answer: 3

Explanation:

The function F(x)= 2/(x-1)(x+3)(x+8) has 3 vertical asymptotes.

x= 1 , x= -3 , x= -8

Step 1 - Factor the denominator

• (x-1)(x+3)(x+8)

* In this case it is already factored to its upmost ability.*

Step 2- Set the factored denominator to 0,and solve for x.

• (x-1)(x+3)(x+8) = 0
• x= 1 , x= -3 , x= -8

Summary- You have three answers for x. So, therefore the graph of this function has three vertical asymptotes.