Question

A bus is traveling with a uniform acceleration of 2.75 meters/second2. If the initial velocity of the bus is 16.5 meters/second, what will its velocity be after 9.00 seconds?

Answer 1

v=u+at

v = 16.5 + (2.75)*(9) where v is the final speed
u is the initial speed
a is the acceleration
t is the time
v=41.25 m/s

Answer 2

Final speed, v = 41.25 m/s

Step-by-step explanation:

It is given that,

Acceleration of the bus,
`a=2.75\ m/s^2`

Initial velocity of the bus, u = 16.5 m/s

We have to find the velocity (v) of the bus after 9 seconds.

The rate of change of velocity is called as the acceleration of the bus. Mathematically, it can be written as :

`a=(v-u)/(t)`

`v=u+at`

`v=16.5+2.75* 9`

v = 41.25 m/s

So, the final speed of the bus after 9 seconds is 41.25 m/s