Question

Please Help!!!

What is the remainder when (x3 − 6x2 − 42x + 79) is divided by (x + 5)?

A) 7

B) 11

C) 13

D) 14

Answer 1

14

Explanation:

Answer 2

By synthetic division,

-5 | 1 -6 -42 79
. | -5 55 -65
- - - - - - - - - - - - - - - - -
. | 1 -11 13 14


`\implies(x^3-6x^2-42x+79)/(x+5)=x^2-11x+13+(14)/(x+5)`

`\implies x^3-6x^2-42x+79=(x^2-11x+13)(x+5)+14`

When
`x=-5`, you're left with a remainder of 14.