Question

The vertex of this parabola is at (2,-1).when the y value is 0,the x value is 5.what is the coefficient of the squared term in the parabolas equation

Answer 1

Vertex form:
y = a(x-2)^2 -1
solve for a:
0 = a(5-2)^2 -1
1 = a(3)^2
1 = 9a
a = 1/9