How many moles of nh3 can be produced from 13.5 mol of h2 and excess n2?

Question

asked Sep 15, 2018 205k views

1 Answer

Metaphore · Answer 1 · 2018-09-20T03:24:39+0000

Standard equation: N2(g)+3H2(g)==>2NH3(g), so through stoichiometry, (13.5 mol H2)(2 mol NH3/3 mol H2), yielding 9 moles of NH3