Question

A gas occupies 4.00 L at 2.00 atm pressure. At what pressure would the volume be 6.00 L if the temperature remains constant?

Answer 1

P1V1= P2V2
P1= 2
V1=4
V2=6
answere= (8/6)

Answer 2

The final pressure would be 1.33 atm

Step-by-step explanation:

Given:

Initial volume of the gas, V1 = 4.00 L

Initial pressure, P1 = 2.00 atm

Final volume, V2 = 6.00 L

To determine:

The final pressure P2 of the gas

Step-by-step explanation:

Based on the ideal gas equation:

`PV = nRT`

where: n = number of moles,

R = gas constant and T = temperature

At constant Temperature the gas law reduces to,

`PV = constant\\\\P1V1 = P2V2\\\\P2 = (P1V1)/(V2) = (2.00atm*4.00L)/(6.00L) =1.33\ atm`