If sound is increased in intensity by a factor of 100,000, what is the change in decibels?

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asked Sep 1, 2018 29.6k views

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Hephaestus · Answer 1 · 2018-09-06T19:30:03+0000

If the sound is increased in intensity by a factor of 100,000 , the change in decibels could be found with this formula:

ΔL = 10 log (x) ----------- x is the intensity factor

ΔL= 10 log (100,000)

ΔL= 10 Log (10^5)

ΔL= 50 dB

If sound is increased in intensity by a factor of 100,000, what is the change in decibels?

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