Question

3sec^X+8=10sec^X then find the value of tanx

Answer 1

Presumably, "sec^X" is supposed to say
`\sec^2x`.


`3\sec^2x+8=10\sec^2x\iff7\sec^2x-8=7(\sec^2x-1)-1=7\tan^2x-1=0`

`\implies\tan^2x=\frac17`

`\implies\tan x=\pm\frac1{\sqrt7}`