If two parents are homozygous dominant for a recessive trait , what is the probability they child does not have this trait ?

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asked Nov 2, 2018 160k views

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Priojeet Priyom · Answer 1 · 2018-11-06T14:25:51+0000

If you set up a punnett square, the results from a cross between these parents AA x AA (homozygous dominant) would be something like (AA, AA, AA, AA)

From the results, we can see there is a 100% chance the child would have the trait.

If two parents are homozygous dominant for a recessive trait , what is the probability they child does not have this trait ?

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