(y-7)(y+3)<(y-3)(y+3)

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asked Nov 21, 2018 93.1k views

1 Answer

Ivan Nevostruev · Answer 1 · 2018-11-25T08:29:12+0000

If you work out both sides, you get:

y^2 - 4y - 21 < y^2 - 9
-4y < 12
y > -3 (remember, if you divide by a negative number, the less-than flips and becomes a greater than)

(y-7)(y+3)<(y-3)(y+3)

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