Question

How do you find the area of a sector with a central angle of 170 degrees and a diameter of 9.1

Answer 1

`\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=\textit{angle in degrees}\\ r=radius=(diameter)/(2)\\ ----------\\ \theta=170\\ diameter=9.1\\ r=(9.1)/(2)=4.55 \end{cases}\implies A=\cfrac{170\cdot \pi \cdot 4.55^2}{360}`