asked 223k views
2 votes
Which is the minimum value of the function y=x^2+8x+7

asked
User Mimere
by
8.2k points

2 Answers

5 votes
You can do this by completing the square.
Y=x^2 + 8x + 7
= (x+4)^2 -16+7
= (x+4)^2 - 9

Minimum value = -9
answered
User Tolu
by
8.4k points
4 votes
The minimum value of the function is (-4, -9).
answered
User SorcyCat
by
8.5k points

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