Question

What is the equation of a circle with center (-2, 3) and radius 4?

A) (x+2)^2 + (y-3)^2 = 16
B) (x-2)^2 + (y+3)^2 = 16
C) (x+2)^2 + (y-3)^2 = 4
D) (x+2)^2 - (y-3)^2 = 16

Answer 1

(y-k)² + (x-h)² = R² , where h and k are the coordinated of the center (-2, 3)
Plug in :

(y-3)² + (x+2)² = 4² ==>(y-3)² + (x+2)² =16 Answer A