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Use the Factor Theorem to determine whether h(x)=x-2 is a factor of f(x)=x^3+x^2-4x+4

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If (x-2) is a factor of P(x), then what do you think P(x) will be if x = 2? If x is 2 then won't x-2 be zero? And if a factor of of P(x) is zero, won't P(x) be zero, too (regardless of what the other factor is)?

So the "proper value" to test is x=2. If P(2) = 0 then x-2 must be a factor and if P(2) is not zero then x-2 is not a factor is

.3x-x+2=4



I'll leave it up to you so simplify this and find out if x-2 is a factor.

P.S. As I indicated above you use P(2) to see if (x-2) is a factor. P(-2) checks to see if (x-(-2)) or (x+2) is a factor. P(-2) does not check for a factor of (x-2)! Please redo the problem and see what P(2) works out to be!
answered
User Jesse Vogt
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4 votes

Answer:

NO

Explanation:

just took the unit test review

answered
User Bartosz Hernas
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