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Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper. What is the probability of select…
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Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper. What is the probability of select…
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Jul 6, 2018
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Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper.
What is the probability of selecting an odd number followed by an even number?
A. 1/4
B. 1/5
C. 5/18
D. 2/9
Mathematics
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Silvio Biasiol
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5/10 * 5/9
1/2 * 5/9
5/18
Chunpoon
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Jul 8, 2018
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Chunpoon
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Note: Since the question states that the first number is not replaced, the second number is "dependent" on the first.
Problem Solved:
Probability (odd, then even) = (5/10) x (5/9)
(5/10) x (5/9)
= 25/90
= 5/18 (simplified)
Answer: C. 5/18
Ivan Pirog
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Jul 11, 2018
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