Question

A boy throws a baseball across a field. The ball reaches its maximum height, 18 meters, after 1 second. After approximately 2.3 seconds, the ball lands on the ground. The ball’s motion can be modeled using the function f(x) = –10x2 + 20x + 8. What is the height of the ball 1.5 seconds after it is thrown?

Answer 1

The height of the ball is 15.5 Meters assuming that the equation above is:
f(x) = -10x^2 + 20x + 8.
To solve this, all you have to do is plug in 1.5 for "x" and then solve.

The new equation you need to solve would look like this: f(1.5) = -10(1.5)^2 + 20(1.5) + 8
When solved you should get the answer 15.5 meters.

You're welcome