What are the possible values of x in 6x^2 + 432 = 0?

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asked Feb 25, 2018 104k views

1 Answer

Gabriel Meono · Answer 1 · 2018-03-01T03:59:36+0000

Hello there.

What are the possible values of x in 6x^2 + 432 = 0?

First, subtract 432 from both sides

Next, divide both sides by 6 and take the square root,

Final answer:
No solutions.

What are the possible values of x in 6x^2 + 432 = 0?

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