Question

An elevator is moving upward at 1.20 m/s when it experiences an acceleration of 0.31 downward over a distance of 0.75m. What will its final velocity be?

Answer 1

Info.: Vi = 1.20 m/s, a = 0.31 m/s^2, Δx = 0.75 m, Vf = ?

Vf = sqrt (Vi^2 + 2aΔx) = sqrt ((1.20 m/s)^2 + 2(0.31 m/s^2 * 0.75 m))
= 0.99 m/s