Question

The sum of 6 consecutive integers is 393. What is the third number in this sequence?

Answer 1

so, let first be x

then , second be x+1
and so on....

so the eqn will be,

x+x+1+x+2+x+3+x+4+x+5=393
6x= 393-15
x= 378/6
x= 63

so first no I 63
second will be 64

and third (your answer) will be 65 !!

Answer 2

x + x+1 + x+2 + x+3 + x+4 + x+5 = 393
Therefore, 6x+15=393
6x = 378
Thus, x = 63.

So the first is 63, the second is 64, the third is 65, fourth is 66, fifth is 67, and six is 68.

63 + 64 + 65 + 66 + 67 + 68 = 393

65 is the third number in this sequence.