Question

Divide squared 9x^2 by squared 18y^2

Answer 1

`(√(9x^2))/(√(18y^2))=(x√(3^2))/(y√(3^2*2))=(\\ot3x)/(\\ot3y\sqrt2)=(x)/(y\sqrt2)=(x)/(y\sqrt2)*(\sqrt2)/(\sqrt2)=(x\sqrt2)/(2y)`
Answer = C

Answer 2

Answer(C)

√(9x^2)= 3x
√(18y^2)=3y/√2= 3y/√2 X √2/√2
=3√2y/2