Question

The equation of a circle is ​ (x−10)² + (y−8)² = 256 ​

What is the center of the circle?



Explain your answer. Thank you^-^.

Answer 1

`(x-a)^2+(y-b)^2=r^2`
(x−10)² + (y−8)² = 256

(a,b) = (10,8) Center of the circle ​