Question

A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 9 over 20. The probability of the arrow landing on a section colored blue is 6 over 20. What is the probability of the arrow landing on a green-colored section?.

Answer 1

The answer would be 5/20 because you add the probability of red and blue (15/20), then subtract from the total (20) which would make it 5/20.

Answer 2

Answer: Probability of the arrow landing on a green colored section is
`(1)/(4)`

Explanation:

Since we have given that

Probability of the arrow landing on a section colored blue =
`(6)/(20)`

Probability of the arrow landing on a section colored red =
`(9)/(20)`

Since there are only three sections i.e. red, blue and green.

We need to find the probability of the arrow landing on a section colored green.

Required probability is given by

`1-((9)/(20)+(6)/(20))\\\\=1-(15)/(20)\\\\=(20-15)/(20)\\\\=(5)/(20)\\\\=(1)/(4)`

Hence, Probability of the arrow landing on a green colored section is
`(1)/(4)`