Question

HI I need help please
Its in the pictures

Answer 1

1.


`r=32\,\text{units}\\\\ A=\pi\cdot r^2=\pi\cdot32^2=1024\pi\,\,\text{units}^2`

Answer D.

2.
From secant theorem, we know, that:


`|AE|\cdot|BE|=|DE|\cdot|CE|`

and from picture:


`|BE|=x+1\\\\|CE|=x+4\\\\|AE|=11+x+1=x+12\\\\|DE|=1+x+4=x+5`

So we can calculate:


`|AE|\cdot|BE|=|DE|\cdot|CE|\\\\(x+12)\cdot(x+1)=(x+5)\cdot(x+4)\\\\ x^2+12x+x+12=x^2+5x+4x+20\\\\ x^2+13x+12=x^2+9x+20\quad|-x^2\\\\13x+12=9x+20\quad|-9x\\\\4x+12=20\quad|-12\\\\4x=8\quad|:4\\\\\boxed{x=2}`