Question

The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probability that the 2 does not end up face down?

Answer 1

long answer short, its 3/4

Answer 2

probablity=desrierdoutcomes/totalposssibleotcomes

totalpossible=numberofsides=4

desired is NOT 2
there are 1,2,3,4
the ones that are NOT 2 are 1,3,4
those are 3 sides

so probablity that it isn't 2, is 3/4 or 75%