Question

A helium balloon is filled in a store at room temperature (24°C) to a volume of 6.5 L. The balloon is then taken outside where the temperature is only 8°C. What is the new volume of the balloon? 6.1 L 6.9 L 2.2 L 19 L

Answer 1

6.1 L

Step-by-step explanation:

Answer 2

Applying Charles' Law, in which as volume increases, temperature increases and as it decreases, the temperature also decreases. Hence,
`( V_(1) )/( T_(1) ) = ( V_(2) )/( T_(2) )`


`V_(1) = 6.5 L \\ T_(1) = (24 + 273) \\ V_(2) = X \\ T_(2) = (8 + 273)`
note: Temperature in Celsius shall be converted to Kelvin

Simplifying:

`(6.5)/(297) = (X)/(281)`

x = { 6.5 (281) } / 297
x = 6.1 L