Question

A trapeziodal pyramid has a volume 2856insquared the height of the pyramid is 24in and the lengths of the 2 two bases of the trapeziodal base are 13 and 29 in what is the height of the trapeziodal base

Answer 1

V = 1/3Bh
B = 1/2(b1 + b2)t

V = 1/3[1/2(b1 + b2)t] * h
h = 24
b1 = 13
b2 = 29
t = ?
V = 2856

Substitute:
2856 = 1/3[1/2(13 + 29)t](24)
2856 = 1/6(42)(24)t
2856 = 7(24)t
2856 = 168t
t = 2856/168 = 17 in height of the trapeziod