Question

Solve log2(x – 1) = log12(x – 1) by graphing.

Answer 1

x=2

Explanation:

Answer 2

By graphing ;
`\log_2 (x-1) = \log_(12) (x-1)` only for x =2

Explanation:

Solve:
`\log_2 (x-1) = \log_(12) (x-1)`

let
`y_1=\log_2 (x-1)` and
`y_2=\log_(12) (x-1)`

To find the x for which
`y_1= y_2`

A graph of these
`y_1=\log_2 (x-1)` and
`y_2=\log_(12) (x-1)` shows us that the graph intersect.

This implies that there is a single (x, y) value that satisfies both equations.

i.,e (2, 0)

Therefore,
`\log_2 (x-1) = \log_(12) (x-1)` only when x =2

You can see the graph as shown below: