Question

t2 + 2t + 1 = 0 Solve using the quadratic formulaWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.

Answer 1

t²+ 2t + 1 = 0

a=1, b=2 & c=1 The formula is x'=[-b+√(b²-4ac)]/(2a)

and====================>x"=[-b-√(b²-4ac)]/(2a)

x' = [-2+√(2²-4(1)] / 2(1) ===> x' = -2/2 ==> x' =-1 & x" = -1
x'=x"= -1

Answer 2

t=-1 hope i helped im sure it is right