Question

Use the three steps to solve the problem.

One number is 11 more than twice another number. If the sum of the numbers is twice their difference, find the numbers

Answer 1

11 , 33

Explanation:

Write out the equation

2x + 11 + x = 2(2x + 11 - x)

Simplify

3x + 11 = 4x + 22 - 2x

3x + 11 = 2x + 22

Solve for x

3x = 2x + 11

x = 11

Now we have x, find the other number

2(11) + 11 = 33

11 and 33 are the two numbers.

Answer 2

Okay, so
a=2b+11
a+b = 2(a-b)

now solve

a+b = 2a-2b
3b = a, put that into the 1st equation:

3b = 2b+11
b=11
a = 2(11) +11 = 33

check in the 2nd equation:
33+11 = 2(33-11)
44 = 2(22)
44 = 44