Question

At a gas station, 84% of customers buy gasoline. Only 5% of customers buy gasoline and a beverage.What is the probability that a customer who buys gasoline also buys a beverage?

Answer 1

The solution would be like this for this specific problem:

5%/84% = 5/84

The answer is 0.0595238095238095. And rounding our answer to he nearest tenth (percent), we’d be getting .060.

If you have any other questions, please don’t hesitate to ask me.

Answer 2

0.06 or 6% probability

Explanation:

At a gas station, 84% of customers buy gasoline

P (A) =
`(84)/(100)` = 0.84

5% of customers buy gasoline and a beverage

P (B) =
`(5)/(100)` = 0.05

Equation of conditional probability = P (A and B) = P(A) × P(B/A)

= P(B/A) = P (A and B) / P(A)

= P ( B/A ) =
`(0.05)/(0.84)`

= 0.0595 ≈ 0.060 or 6%

The probability that a customer who buys gasoline also buys a beverage is 0.060 or 6%.