Question

What is the 12th term of the sequence 3,6,12,24....

Answer 1

The answer to this is:

6,144

Answer 2

`a_(0)`=3

r=common ratio: 12/6=2; 6/3=2

r=2,
`a_(n)`=
`2^(n-1)`*3

plug in 12 for n:


`a_(12)`=
`2^(12-1)`*3


`a_(12)`=
`2^(11)`*3


`a_(12)`=2048*3


`a_(12)`=6144

The twelfth term in the sequence is 6144