asked 81.5k views
5 votes
Complete the paragraph proof.

Given: M is the midpoint of PK

PK ⊥ MB

Prove: △PKB is isosceles

It is given that M is the midpoint of PK and PK ⊥ MB. Midpoints divide a segment into two congruent segments, so PM ≅ KM. Since PK ⊥ MB and perpendicular lines intersect at right angles, ∠PMB and ∠KMB are right angles. Right angles are congruent, so ∠PMB ≅ ∠KMB. The triangles share MB, and the reflexive property justifies that MB ≅ MB. Therefore, △PMB ≅ △KMB by the SAS congruence theorem. Thus, BP ≅ BK because

(corresponding parts of congruent triangles are congruent)

(base angles of isosceles triangles are congruent)

(of the definition of congruent segments)

(of the definition of isosceles triangles)

Finally, △PKB is isosceles because it has two congruent sides.

2 Answers

6 votes

Answer:

corresponding parts of congruent triangles are congruent

Explanation:

answered
User Pyroscope
by
8.0k points
3 votes
Thus, BP ≅ BK because corresponding parts of congruent triangles are congruent.
"Corresponding parts of congruent triangles are congruent" (CPCTC) states that if two or more triangles are congruent, then all of their corresponding angles and sides are congruent as well.
answered
User David Jarvis
by
7.7k points
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