You select a card at random. Without replacing the card, you select a second card. Find the probability. P(M, then H)

Question

asked Sep 25, 2018 220k views

1 Answer

Buzypi · Answer 1 · 2018-09-28T13:34:48+0000

Answer:

The correct option is C.

Explanation:

The alphabets written on cards are "MATHEMATICS".

We select first card after that we select second card without replacement.

We have to find the probability of (M, then H)

The total alphabets are 11.

The total number of card of M alphabet is 2. The total number of card of H alphabet is 1.

Probability is defined as

$P=\frac{\text{Possible outcomes}}{\text{Total outcomes}$

The probability of selecting card of M alphabet is,

P(M)=(2)/(11)

Now the total remaining card are 10, because the 1 card is drawn without replacement.

The probability of selecting card of H alphabet is,

P(H)=(1)/(10)

So, probability of (M, then H)

$P(M\text{, then }H)=P(M)* P(H)$

$P(M\text{, then }H)=(2)/(11)* (1)/(10)$

$P(M\text{, then }H)=(2)/(110)$

$P(M\text{, then }H)=(1)/(55)$

Therefore the probability of (M, then H) is
(1)/(55) . Option C is correct.