Question

What is the approximate value of x in the equation Log5^(15)=x+3

Answer 1

x=-3+15log(5)
x~7.48455006

Answer 2

if you mean

`log_5(15)=x+3`

remember


`log_a(b)=c` translates to
`a^c=b` so

`log_5(15)=x+3` translates to
`5^(x+3)=15` which is equal to

`(5^x)(5^(3))=15`

`(5^x)(125)=15`
divide both sides by 125

`5^x= (3)/(25)`
take the ln of both sides

`ln(5^x)= ln((3)/(25))`

`xln(5)= ln ((3)/(25))`
divide both sides by ln(5)
x=ln(3/25)/ln(5)
use calculator to evaluate
x≈-1.31739
the aproximate value is -1.32 to the hundreth