Question

Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number. (Hint: You can use variables to represent the digits of a number. If a two-digit number has the digit x in tens place and y in one’s place, the number will be 10x + y. Reversing the order of the digits will change their place value and the reversed number will 10y + x.) The difference of the original two-digit number and the number with reversed digits is

Answer 1

let xy be this number:


5(x+y) = (10x+y)-13==> -5x +4y = -132

& 4(y+x) =4(10y+x) - 21==> 3x-6y = -21

Slove this equation & you will get x=9 & y=8

Answer 2

The anwser would be 27 because when done reversed it gives u the start off numbers