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5 consecutive integers of 265

5 consecutive integers of 265
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4 votes
5 consecutive integers of 265

asked
User Sambeth
by
8.2k points

1 Answer

3 votes
n+n+1+n+2+n+3+n+4=265

5n+10=265

5n=255

n=51

So the integers are:

51,52,53,54, and 55
answered
User Antoine Bourlart
by
9.0k points
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