Question

How to solve this???
e^(2x) - e^x = 6

Answer 1

`e^(2x)-e^x=6`

`(e^x)^2-e^x-6=0`

`(e^x-3)(e^x+2)=0`


`e^x=3`

`e^x=-2`

therefore
`x=\ln3` and
`x=\ln-2`
because
`\ln-2` doesn't exist, the only solution to your equation is
`x=\ln3`