Question

Factor completely 2x3y4 − 8x2y3 + 6xy2. 2(x3y4 − 4x2y3 + 3xy2) 2x(x2y4 − 4xy3 + 3y2) 2xy2(x2y2 − 4xy + 3) Prime

Answer 1

C. 2xy2(x2y2 − 4xy + 3)

Explanation:

Answer 2

The factorised term is:

`2xy^2(x^2y^2-4xy+3)`

Explanation:

We are asked to factor the algebraic expression given as:

`2x^3y^4-8x^2y^3+6xy^2`

Now we will take out the variable which is common among all the terms and write the remaining expression in parantheses.

As
`2xy^2` is common among all the terms hence we write this term out of the parantheses and the remaining term inside it as to obtain then simplified expression as:

`2xy^2(x^2y^2-4xy+3)`