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2 votes
How does the value of Ka and Kb compare with the concentrations of hydronium ion and hydroxide ion?

Ka X Kb= [H3O+][OH-]
Ka X Kb> [H3O+][OH-]
Ka X Kb< [H3O+]+[OH-]
Ka X Kb+ [H3O]/[OH-]

2 Answers

2 votes

Answer:

The correct answer is A, Ka × Kb = [H₃0⁺][OH⁻]

I hope this helps, have a good day and good luck! :)

How does the value of Ka and Kb compare with the concentrations of hydronium ion and-example-1
answered
User Stefan Drissen
by
8.2k points
4 votes
Assuming that we are given the values of Ka and Kb, these can be rewritten and represented by the concentration of the Hydronium ion and Hydroxide Ion:

Hydronium ion: [H3O+]
Hydroxide ion: [OH-]

Ka is the equilibrium constant of an acid which dissociates to a hydronium ion and its cation.
Kb is the equilibrium constant of a base which dissociates to a hydroxide ion and its anion.

So,

Ka x Kb = [H3O+][OH-]
answered
User Jack Gibson
by
7.5k points
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