Question

4x/x^2-3x-18 - 2x/x^2+6x+9

Answer 1

`\bf \cfrac{4x}{x^2-3x-18}-\cfrac{2x}{x^2+6x+9}\qquad \begin{array}{lcclll} x^2&-3x&-18\\ &\uparrow&\uparrow \\ & -6+3&-6\cdot 3\\\\ --&--&--\\\\ x^2&+6x&+9\\ &\uparrow &\uparrow \\ &3+3&3\cdot 3 \end{array}\\\\ -----------------------------\\\\ \cfrac{4x}{(x-6)(x+3)}-\cfrac{2x}{(x+3)(x+3)}\qquad LCD\to (x-6)(x+3)(x+3) \\\\\\ \cfrac{4x(x+3)-2x(x-6)}{(x-6)(x+3)(x+3)}\implies \cfrac{4x^2+12x-2x^2+12x}{(x-6)(x+3)(x+3)} \\\\\\ \cfrac{2x^2+24x}{(x-6)(x+3)(x+3)}\implies \cfrac{2x(x+12)}{(x-6)(x+3)(x+3)}`

Answer 2

a good math calculator is called math-way it shows step by step answers. I hope this helps