Register

2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)

2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)
asked 199k views
1 vote
2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)

asked
User Agnaramon
by
8.3k points

1 Answer

5 votes
2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)
-6k^2+8k+6k^2+60=4k^2+8k-4k^2-10k
8k+60=8k-10
-10k=60
k=-6

answered
User Chris Bacon
by
7.7k points
← Prev Question Next Question →

Related questions

User Daniel Hao
asked Nov 4, 2024 157k views
(2k^3-7k^2+3k)-(4k^2+5k)
Daniel Hao asked Nov 4, 2024
by Daniel Hao
8.6k points
1 answer
2 votes
157k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!