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Given ΔBAE is isosceles with base angles ∠BEA and ∠EBA and that ∠AEC = 115°, is ΔEBC ~ ΔAEC? If so, by what criterion?

Given ΔBAE is isosceles with base angles ∠BEA and ∠EBA and that ∠AEC = 115°, is ΔEBC ~ ΔAEC? If so, by what criterion?
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Given ΔBAE is isosceles with base angles ∠BEA and ∠EBA and that ∠AEC = 115°, is ΔEBC ~ ΔAEC? If so, by what criterion?

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User Miaoyi
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1 Answer

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ΔEBC ~ ΔAEC by AA criterion
answered
User Avi Chalbani
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